Quick question
- Thread starter needaSRX
- Start date
62mm / (25.4mm/in) = 2.4409in diameter ; PI = 3.141592
Are of a circle = [(PI) x radius^2] = [3.141592 x (2.4409/2)^2] = 4.6794 sq inches.
Now if you want to know what the cubic inch displacement, just take the area times the stroke and you have it.
Mills
Are of a circle = [(PI) x radius^2] = [3.141592 x (2.4409/2)^2] = 4.6794 sq inches.
Now if you want to know what the cubic inch displacement, just take the area times the stroke and you have it.
Mills
very good reading info http://www.datafan.com/TunersHandbook/2-strokefiltered.html
I'm trying to figure out this formula for an SRX 700 69mm bore and 62mm stroke
BHP=PLAN/33000
P= Brake Mean Effective pressure in PSI
L= Piston stroke in feet
A= area of one piston in inches
N= Number of power strokes per minute
BHP=PLAN/33000
P= Brake Mean Effective pressure in PSI
L= Piston stroke in feet
A= area of one piston in inches
N= Number of power strokes per minute
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bluemonster1
LIFE MEMBER ONLY ONCE!!!
way to much reading there my friend,would take me like 2 weeks to read that and then I would have to start over because I would of forgotten what I read.I am not a reader,don't like reading books,small articles maybe and that is it.
glockwise
New member
needaSRX said:
You can't figure that out with out measuring it. Brake horse power is measured by an absorption dynamometer or "brake". The dyno absorbs the rotation of the pto and calculates all that tough math so you don't have to.
Glock is right, you can't calculate it because you don't have the (P) for the formula. THe (P) comes from the pad pressure applied to the flywheel of a brake dyno.